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Trigonometric Functions and Their Properties

Neurocoda
Neurocoda
2026-07-03 12:46:42 1.2k Words 7 Mins ...

Trigonometric Functions

Standard Forms

{sinθ=oppositehypotenusecosθ=adjacenthypotenusetanθ=sinθcosθ\begin{cases} \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} \\\\ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} \\\\ \tan \theta = \frac{\sin \theta}{\cos \theta} \end{cases}

Basic Properties

Sine Function sin(x)\sin(x)

y=sinxy = \sin x

  • Period: 2π2\pi
  • Symmetry: Odd function
  • Extremum: (π2+2kπ,1)\left( \frac{\pi}{2}+2k\pi, 1 \right)
  • Zeros: kπ (kZ)k\pi \ (k \in \mathbb{Z})

Cosine Function cos(x)\cos(x)

y=cosxy = \cos x

  • Period: 2π2\pi
  • Symmetry: Even function
  • Extremum: (2kπ,1)(2k\pi, 1)
  • Zeros: π2+kπ\frac{\pi}{2}+k\pi

Tangent Function tan(x)\tan(x)

y=tanx=sinxcosxy = \tan x = \frac{\sin x}{\cos x}

  • Period: π\pi
  • Asymptotes: x=π2+kπx = \frac{\pi}{2}+k\pi
  • Range: R\mathbb{R}
  • Special points: Passes through origin, symmetric about the center of each period

Core Properties

Derivatives and Integrals

FunctionDerivativeIntegral
sinx\sin xcosx\cos xcosx+C-\cos x + C
cosx\cos xsinx-\sin xsinx+C\sin x + C
tanx\tan xsec2x\sec^2 x$-\ln

Important Identities

Pythagorean Identity:

sin2x+cos2x=1\sin^2x + \cos^2x = 1

Sum and Difference Formulas:

sin(a±b)=sinacosb±cosasinb\sin(a\pm b) = \sin a \cos b \pm \cos a \sin b cos(a±b)=cosacosbsinasinb\cos(a \pm b) = \cos{a} \cos{b} \mp \sin{a} \sin{b}

Comparison of Functions

PropertySine FunctionCosine FunctionTangent Function
Initial value010
ExtremumOdd multiples of π/2\pi/2Even multiples of π\piNone
Periodicity2π2\pi2π2\piπ\pi
AsymptotesNoneNonePresent
3030^\circ4545^\circ6060^\circ
sinsin12\frac{1}{2}22\frac{\sqrt{2}}{2}32\frac{\sqrt{3}}{2}
coscos32\frac{\sqrt{3}}{2}22\frac{\sqrt{2}}{2}12\frac{1}{2}
tantan33\frac{\sqrt{3}}{3}113\sqrt{3}

Reduction Formulas

Summary

  1. Split the angle: Express the target angle as kπ2±α\frac{k\pi}{2} \pm \alpha
  2. Determine parity: Check if kk is odd or even to decide whether to change the function name
  3. Determine quadrant: Identify the quadrant of kπ2±α\frac{k\pi}{2} \pm \alpha and determine the sign of the new function
  4. Combine results: Combine the sign and function name to obtain the final expression

Core Principle Analysis

Odd changes, even remains: Transformation of function names

When the angle takes the form kπ2±α\frac{k\pi}{2} \pm \alpha (kZk \in \mathbb{Z}):

  • Odd changes: If kk is odd, the trigonometric function name changes to its cofunction (sine↔cosine, tangent↔cotangent)
  • Even remains: If kk is even, the function name remains unchanged

Example analysis:

  1. sin(π2+α)\sin\left(\frac{\pi}{2} + \alpha\right): k=1k=1 (odd), sin\sin changes to cos\coscosα\cos\alpha
  2. cos(π+α)\cos(\pi + \alpha): k=2k=2 (even), name unchanged → cosα\cos\alpha
  3. tan(3π2α)\tan\left(\frac{3\pi}{2} - \alpha\right): k=3k=3 (odd), tan\tan changes to cot\cotcotα\cot\alpha
Sign depends on quadrant: Determining the sign of the function value

Assuming α\alpha is an acute angle, treat kπ2±α\frac{k\pi}{2} \pm \alpha as a whole angle, and determine the sign of the result based on its quadrant:

Quadrant sign mnemonic:
|400

All positive in first quadrant, sine in second, tangent and cotangent in third, cosine in fourth

Steps:

  1. Determine the quadrant of kπ2±α\frac{k\pi}{2} \pm \alpha
  2. Determine the sign of the new function based on the quadrant
  3. Assign the sign to the simplified result

Example analysis:

  • cos(π+α)\cos\left(\pi + \alpha\right):

    1. Even remains
    2. π+α\pi + \alpha is in the third quadrant
    3. Cosine is negative in the third quadrant
    4. Result is cosα-\cos\alpha
  • sin(3π2α)\sin\left(\frac{3\pi}{2} - \alpha\right):

    1. Odd changes
    2. 3π2α\frac{3\pi}{2} - \alpha is in the third quadrant
    3. Sine is negative in the third quadrant
    4. Result is cosα-\cos\alpha

Comprehensive Application Examples

Example 1: Simplify sin(5π2α)\sin\left(\frac{5\pi}{2} - \alpha\right)

  1. Split angle: 5π2=2π+π2\frac{5\pi}{2} = 2\pi + \frac{\pi}{2}k=5k=5 (odd)
  2. Function name changes: sin\sincos\cos
  3. Quadrant determination: 5π2α\frac{5\pi}{2} - \alpha is in the first quadrant, cosine is positive
  4. Result: cosα\cos\alpha

Derivation:

sin(5π2α)=sin(2π+π2α)=cosα\sin\left(\frac{5\pi}{2} - \alpha\right) = \sin\left(2\pi + \frac{\pi}{2} - \alpha\right) = \cos\alpha

Example 2: Compute tan(7π2+α)\tan\left(\frac{7\pi}{2} + \alpha\right)

  1. Split angle: 7π2=3π+π2\frac{7\pi}{2} = 3\pi + \frac{\pi}{2}k=7k=7 (odd)
  2. Function name changes: tan\tancot\cot
  3. Quadrant determination: 7π2+α\frac{7\pi}{2} + \alpha is in the fourth quadrant, cotangent is negative
  4. Result: cotα-\cot\alpha

Derivation:

tan(7π2+α)=tan(3π+π2+α)=cotα\tan\left(\frac{7\pi}{2} + \alpha\right) = \tan\left(3\pi + \frac{\pi}{2} + \alpha\right) = -\cot\alpha

Special Cases

Angles beyond 2π2\pi:

  • Reduce the angle modulo 2π2\pi before determining. For example, 9π2α\frac{9\pi}{2} - \alpha simplifies to π2α+4π\frac{\pi}{2} - \alpha + 4\pi, so k=9k=9 (odd)

Negative angles:

  • Use parity to convert. For example, sin(α)=sinα\sin(-\alpha) = -\sin\alpha (odd function property)

Inverse Trigonometric Functions

Standard Forms

{θ=arcsin(oppositehypotenuse)θ=arccos(adjacenthypotenuse)θ=arctan(oppositeadjacent)\begin{cases} \theta = \arcsin\left(\dfrac{\text{opposite}}{\text{hypotenuse}}\right) \\ \theta = \arccos\left(\dfrac{\text{adjacent}}{\text{hypotenuse}}\right) \\ \theta = \arctan\left(\dfrac{\text{opposite}}{\text{adjacent}}\right) \end{cases}

|500

FunctionDomainRangeMonotonicity
arcsinx\arcsin x[1,1][-1,1][π2,π2][\frac{-\pi}{2},\frac{\pi}{2}]Strictly increasing
arccosx\arccos x[1,1][-1,1][0,π][0,\pi]Strictly decreasing
arctanx\arctan xR\mathbb{R}(π2,π2)(\frac{-\pi}{2},\frac{\pi}{2})Strictly increasing

Basic Properties

Arcsine Function arcsin(x)\arcsin(x)

y=arcsinxy = \arcsin x

|500

  • Domain: x[1,1]x \in [-1, 1]
  • Range: [π2,π2]\left[ -\frac{\pi}{2}, \frac{\pi}{2} \right]
  • Derivative:
dydx=11x2(1<x<1)\frac{dy}{dx} = \frac{1}{\sqrt{1 - x^2}} \quad (-1 < x < 1)
  • Monotonicity: Strictly increasing
  • Special values:
    • arcsin(0)=0\arcsin(0) = 0
    • arcsin(12)=π6\arcsin\left( \frac{1}{2} \right) = \frac{\pi}{6}

Arccosine Function arccos(x)\arccos(x)

y=arccosxy = \arccos x

  • Domain: x[1,1]x \in [-1, 1]
  • Range: [0,π][0, \pi]
  • Derivative:
dydx=11x2(1<x<1)\frac{dy}{dx} = -\frac{1}{\sqrt{1 - x^2}} \quad (-1 < x < 1)
  • Monotonicity: Strictly decreasing
  • Identity:
arccosx+arcsinx=π2\arccos x + \arcsin x = \frac{\pi}{2}

Arctangent Function arctan(x)\arctan(x)

y=arctanxy = \arctan x

|500

  • Domain: R\mathbb{R}
  • Range: (π2,π2)\left( -\frac{\pi}{2}, \frac{\pi}{2} \right)
  • Derivative:
dydx=11+x2\frac{dy}{dx} = \frac{1}{1 + x^2}
  • Asymptotes: y=±π2y = \pm \frac{\pi}{2}
  • Symmetry:
arctan(x)=arctanx\arctan(-x) = -\arctan x

Typical applications:
As xx \to \infty, arctanxπ2\arctan x \to \frac{\pi}{2}
Integration formula:

1x2+a2dx=1aarctan(xa)+C(a>0)\int \frac{1}{x^2 + a^2} dx = \frac{1}{a} \arctan\left( \frac{x}{a} \right) + C \quad (a > 0)

Effects of Parameters on Graphs

Taking sin(x)\sin(x) as an example:

Basic Parameters

Amplitude Modulation:

y=AsinxPeak heightAy = A\sin x \quad \Rightarrow \quad \text{Peak height} |A|

Frequency Change:

y=sinωxPeriodT=2πωy = \sin \omega x \quad \Rightarrow \quad \text{Period} T = \frac{2\pi}{\omega}

Phase Shift:

y=sin(x+ϕ)Graph shifts left by ϕy = \sin(x + \phi) \quad \Rightarrow \quad \text{Graph shifts left by }\phi

Composite Waveform Example:

y=2sin(3xπ/4)Properties: amplitude 2, frequency 3, right shift π12y = 2\sin(3x - \pi/4) \quad \text{Properties: amplitude 2, frequency 3, right shift }\frac{\pi}{12}

Graph Transformations

Horizontal Translation (Phase Shift)

Mathematical expression:

y=sin(x+c)y = \sin(x + c)
  • c<0c < 0: Graph shifts right by cc units
  • c>0c > 0: Graph shifts left by c|c| units
    Example:
y=sin(xπ2)Original peak (π2,1) becomes (π,1)y = \sin\left(x - \frac{\pi}{2}\right) \quad \Rightarrow \quad \text{Original peak } \left(\frac{\pi}{2},1\right) \text{ becomes } (\pi,1)

|625

Vertical Translation

Mathematical expression:

y=sinx+dy = \sin x + d
  • d>0d > 0: Graph shifts up by dd units
  • d<0d < 0: Graph shifts down by d|d| units
    Example:
y=sinx+2Peak value 3, trough value 1y = \sin x + 2 \quad \Rightarrow \quad \text{Peak value } 3 \text{, trough value } 1

|625

Amplitude Modulation

Mathematical expression:

y=Asinxy = A \sin x
  • A>1|A| > 1: Vertical stretch
  • 0<A<10 < |A| < 1: Vertical compression
  • A<0A < 0: Reflection over the xx-axis
    Example:
y=3sinxAmplitude 3, waveform invertedy = -3 \sin x \quad \Rightarrow \quad \text{Amplitude } 3 \text{, waveform inverted}

|625

y=12sinxAmplitude 12, waveform vertically compressedy = \frac{1}{2} \sin x \quad \Rightarrow \quad \text{Amplitude } \frac{1}{2} \text{, waveform vertically compressed}

|625

Period Adjustment (Frequency Change)

Mathematical expression:

y=sin(Bx)y = \sin(Bx)
  • Period: T=2πBT = \frac{2\pi}{|B|}
  • B>1|B| > 1: Horizontal compression (shorter period)
  • 0<B<10 < |B| < 1: Horizontal stretch (longer period)
    Example:
y=sin(2x)T=π (half of original period 2π)y = \sin(2x) \quad \Rightarrow \quad T = \pi \text{ (half of original period } 2\pi\text{)}

|650

y=sin(12x)T=4π (twice the original period 2π)y = \sin(\frac{1}{2}x) \quad \Rightarrow \quad T = 4\pi \text{ (twice the original period } 2\pi\text{)}

Reflection Transformations

  1. Reflection over the xx-axis
    Expression:

    y=sinxAll y-coordinates are negatedy = -\sin x \quad \Rightarrow \quad \text{All y-coordinates are negated}


    Example:

    sin(π2)=1sin(π2)=1\sin\left(\frac{\pi}{2}\right) = 1 \quad \Rightarrow \quad -\sin\left(\frac{\pi}{2}\right) = -1
  2. Reflection over the yy-axis
    Expression:

    y=sin(x)Equivalent to sinx (sin(x)=sinx)y = \sin(-x) \quad \Rightarrow \quad \text{Equivalent to } -\sin x \ (\because \sin(-x) = -\sin x)


    Example:

    sin(π2)=1\sin\left(-\frac{\pi}{2}\right) = -1

Composite Transformation Example

Example Function:

y=3sin(2xπ4)+1y = 3 \sin\left(2x - \frac{\pi}{4}\right) + 1

  1. Amplitude: 33
  2. Period: T=2π2=πT = \frac{2\pi}{2} = \pi
  3. Phase shift: π/42=π8\frac{\pi/4}{2} = \frac{\pi}{8} (right shift by π8\frac{\pi}{8})
  4. Vertical translation: Upward by 11 unit

Final effect:

  • Starting point changes from (0,0)(0,0) to (π8,1)\left(\frac{\pi}{8},1\right)
  • Maximum point: (π8+π4,4)\left(\frac{\pi}{8} + \frac{\pi}{4},4\right)
  • Minimum point: (π8+3π4,2)\left(\frac{\pi}{8} + \frac{3\pi}{4},-2\right)
Title: Trigonometric Functions and Their Properties Author: Neurocoda Created at: 2026-07-03 12:46:42 Link: https://neurocoda.com/zh-TW/posts/trigonometric-functions-and-their-properties-en/ License: This work is licensed under CC BY-ND 4.0.

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